题解 | #输出单向链表中倒数第k个结点#
输出单向链表中倒数第k个结点
https://www.nowcoder.com/practice/54404a78aec1435a81150f15f899417d
while True:
try:
n = int(input())
cha = input().split()
k = int(input())
if k <= n and k > 0:
print(int(cha[-k])) # 输出一个整数
else:
print(0) # 异常返回空指针
except EOFError:
break
