题解 | #在字符串中找出连续最长的数字串#

import java.util.Scanner;

// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        while (in.hasNextLine()) { // 注意 while 处理多个 case
            String s = in.nextLine();
            char[] arr = s.toCharArray();
            StringBuffer sb = new StringBuffer();
            int maxLen = 0;
            boolean isDigit = false;
            for (int i = 0; i < arr.length; i++) {	//此循环遍历所有字符
                if (Character.isDigit(arr[i])) {
                    StringBuffer tempSb = new StringBuffer();
                    int count = 0;
                    for (int j = i; j < arr.length; j++) {	//此循环处理连续的数字
                        if (!Character.isDigit(arr[j])) {
                            break;
                        }
                        tempSb.append(arr[j]);
                        count++;
                    }
                    if (maxLen < count) {
                        sb = tempSb;
                        maxLen = count;
                    } else if (maxLen == count) {
                        sb.append(tempSb);
                    }
                    i = i + count;    //字符下标跳转到已经处理后的下标位置
                }
            }
            System.out.println(sb.toString() + "," + maxLen);
            maxLen = 0;
            sb = new StringBuffer();
        }
    }
}