题解 | #打印日期# C++简单方法

#include <iostream>
using namespace std;

int month[] = {0, 31, 28, 31, 30, 31, 30,31, 31, 30, 31, 30, 31};

int get_mday(int year, int mon) {
    if(mon == 2 && ((year % 4 == 0 && year % 100) || year % 400 == 0)) return month[mon] + 1;
    else return month[mon];
}

int main() 
{
    int year, day;
    while (cin >> year >> day) {
        int mon = 1;
        while (day > get_mday(year, mon)) {
            day -= get_mday(year, mon);
            mon++;
            if(mon > 12) {
                mon -= 12;
                year++;
            }
        }
        printf("%02d-%02d-%02d\n", year, mon, day);
    }
    return 0;
}