题解 | #字符串加解密#

import java.util.Scanner;

// 深刻掌握字符与整型互转以及ASCII码表的记忆程度
public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        while (in.hasNextLine()) {
            String source = in.nextLine();
            String code = in.nextLine();
            System.out.println(code(source, true));
            System.out.println(code(code, false));
        }
    }

    //加密 解密
    public static String code(String source, boolean isEncode) {
        char[] s = source.toCharArray();
        for (int i = 0; i < source.length(); i++) s[i] = resolve(s[i], isEncode);
        return new String(s);
    }


	//真正去解析每一个字符，处理转换
    private static char resolve(char c, boolean isEncode) {
        // 1 数字； 2 小写字母； 3 大写字母； 
        int off = isEncode ? 1 : -1;
        char newc = '0';
        if (48 <= c && c <= 57) {
            newc = (char)((c + off + 10 - '0') % 10 + '0');
        } else if (97 <= c && c <= 123) {
            newc = (char)((c - 'a' + off + 26) % 26 + 'a' - 32);
        } else if (65 <= c && c <= 90) {
            newc = (char)((c - 'A' + off + 26) % 26 + 'a');
        }
        return newc;
    }
}