题解 | #记负均正#

n = int(input())
num = [int(x) for x in input().split()]
count_p, count_n = 0, 0# 分别用于统计正负数的个数
sum = 0
for i in num:
    if i < 0:
        count_n += 1
    elif i > 0:
        count_p += 1
        sum += i
if count_p == 0:
    ave = 0.0
else:
    ave =float(sum/count_p)
print(count_n, '%.1f' %ave)