题解 | #走方格的方案数#DP
走方格的方案数
https://www.nowcoder.com/practice/e2a22f0305eb4f2f9846e7d644dba09b
n, m = list(map(int,input().split()))
dp = [[0 for _ in range(n+1)]for _ in range(m+1)]
#dp[i][j]的含义为从左上角走到坐标为（i，j）的点的走法个数
for i in range(m+1):
for j in range(n+1):
if i == 0 or j == 0:
dp[i][j] = 1
else:
dp[i][j] =dp[i-1][j] + dp[i][j-1]
print(dp[m][n])
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