题解 | #牛牛的二三七整除#

#include <stdio.h>

int main() {
    int a ;
    int b = 0;
    int c = 0;
    int arr[3] = {2,3,7};
    scanf("%d",&a);
    for (b = 0; b < 3; b++) {
        if (a % arr[b] == 0) {
            printf("%d ",arr[b]);
            c++;
        }
    }
    if(c == 0)
    {
        printf("n");
    }
    return 0;
}