题解 | #统计活跃间隔对用户分级结果#
统计活跃间隔对用户分级结果
https://www.nowcoder.com/practice/6765b4a4f260455bae513a60b6eed0af
-- 我的小坑点是在分级时,新晋和流失比较好确认,沉默放在else后面
select user_grade,round(count(1)/(select count(distinct uid) from tb_user_log),2) as ratio
from
-- 第二步:给用户分等级
(select uid,
case when new_date_diff<7 then '新晋用户'
when last_date_diff<7 and new_date_diff>=7 then '忠实用户'
when last_date_diff>=30 then '流失用户'
else '沉睡用户'
end as user_grade
from
-- 第一步:先找出每个用户首日活跃距今天数以及最后一次活跃距今天数的表
(select uid,
datediff((select max(date(out_time)) from tb_user_log),date(min(in_time))) as new_date_diff,
datediff((select max(date(out_time)) from tb_user_log),date(max(out_time))) as last_date_diff
from tb_user_log
group by uid) t1) t2
group by user_grade
order by ratio desc

