题解 | #统计每个学校的答过题的用户的平均答题数#
统计每个学校的答过题的用户的平均答题数
https://www.nowcoder.com/practice/88aa923a9a674253b861a8fa56bac8e5
select
c.university,
sum(c.ansNum) / count(c.ansNum) as avg_answer_cnt
from
(
select
a.university,
count(*) ansNum
from
user_profile a
join question_practice_detail b on a.device_id = b.device_id
group by
a.university,
a.device_id
) c
group by
c.university
order by
c.university asc
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