题解 | #牛客每个人最近的登录日期(二)#
牛客每个人最近的登录日期(二)
https://www.nowcoder.com/practice/7cc3c814329546e89e71bb45c805c9ad
select u.name u_n,c.name c_n,l.date date from (select *,row_number() over(partition by user_id order by date desc) as 'rank' from login ) l join user u on u.id = l.user_id #给login添加一列排序，按照user_id分组、日期降序 join client c on c.id = l.client_id where l.rank = 1 #取rank=1 即每个user_id下面日期最大的值 order by u_n;
