题解 | #n的阶乘#
n的阶乘
https://www.nowcoder.com/practice/97be22ee50b14cccad2787998ca628c8
#include <cstdio>
#include <iostream>
using namespace std;
long long fact(int n){
if(n==0){
return 1;
}else{
return n*fact(n-1);
}
}
int main(){
int n;
while(scanf("%d",&n)!=EOF){
printf("%lld\n",fact(n));
}
return 0;
}
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