题解 | #二分查找-I#
二分查找-I
https://www.nowcoder.com/practice/d3df40bd23594118b57554129cadf47b
/** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param nums int整型一维数组 * @param numsLen int nums数组长度 * @param target int整型 * @return int整型 */ int search(int* nums, int numsLen, int target ) { // write code here if(numsLen == 0) { return -1; } int left = 0; int right = numsLen - 1; int mid; while(left <= right) { mid = (left + right)/2; if(target<nums[mid]) { right = mid - 1; } else if(target>nums[mid]) { left = mid+1; } else if(target == nums[mid]) { return mid; } } return -1; }
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