题解 | #牛牛的金币#
牛牛的金币
https://www.nowcoder.com/practice/35d8e3e569dc49f2a1018d1dc9186998
#include <stdio.h>
#include <math.h>
int main() {
int x = 0;
int y = 0;
int x1 = 0;
int y1 = 0;
while (4 == scanf("%d %d %d %d", &x, &y, &x1, &y1))
{
if (abs(x1 - x) + abs(y1 - y) == 1)
{
if ((y1 - y) > 0)
{
printf("u");
}
else if ((y1 - y) < 0)
{
printf("d");
}
else if ((x1 - x) > 0)
{
printf("r");
}
else if ((x1 - x) < 0)
{
printf("l");
}
printf("\n");
}
}
return 0;
}
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