题解 | #数字反转#
数字反转
https://www.nowcoder.com/practice/2687c5c174cb4f938bdae01f0a19490c
#include<stdio.h>
int reverse(int n){
int m=0;
while (n != 0){
m = m * 10 + n % 10;
n = n / 10;
}
return m;
}
int main(){
int a, b;
while (scanf("%d %d", &a, &b) != EOF){
if (reverse(a + b) == reverse(a) + reverse(b)){
printf("%d\n", a + b);
}
else{
printf("NO\n");
}
}
}
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