题解 | #删除字符串中出现次数最少的字符#暴力求解不多mi

dic_str={}
str=input()
ls=list(str)
ls_del=[]
for iword in str:
    if iword not in dic_str:
        dic_str[iword]=1
    else:
        dic_str[iword]+=1
min=999
for iword in dic_str:
    if dic_str[iword]<min:
        min=dic_str[iword]
for key in dic_str:
    if dic_str[key]==min:
        ls_del.append(key)
for index in range(-1,-1-len(ls),-1):
    if ls[index] in ls_del:
        del ls[index]
        ls.append('')

a=''.join(ls)
print(a)