题解 | #计算日期到天数转换#
计算日期到天数转换
https://www.nowcoder.com/practice/769d45d455fe40b385ba32f97e7bcded
#include <stdio.h>
int main() {
int day_s[12] = {31,28,31,30,31,30,31,31,30,31,30,31};
int year = 0;
int month = 0;
int day = 0;
int out = 0;
scanf("%d %d %d", &year, &month, &day);
if(year % 4 == 0 && year % 100 != 0 || year % 400 == 0) //闰年判断
{
day_s[1] = 29;
}
else {
day_s[1] = 28;
}
for(int i = 0; i<month-1; i++)
{
out += day_s[i];
}
printf("%d",out+day);
return 0;
}
