题解 | #删除字符串中出现次数最少的字符#

//1. 字符串转为数组 遍历之后用对象key存字段 value存出现次数
//2. 遍历对象 用找出value最小值 如果相等 则都存一个数组中
//3. 数组转为字符串 replace替换方法 将相同的替换为空字符串
const readline = require('readline')
const rl = readline.createInterface({
    input:process.stdin,
    output:process.stdout
});
rl.on('line',(line)=>{
    let countRecord = {}
    let inputArray = line.split('');
    for(let i = 0;i<inputArray.length;i++){
        if(!countRecord[inputArray[i]]){
            countRecord[inputArray[i]]=0;
        }
        countRecord[inputArray[i]] += 1
    }
    let target = []
    let count = 0
    for( let k in countRecord){
        if(count == 0){
            target.push(k)
            count=countRecord[k]
        }else if(countRecord[k]<count){
            target.length = 0;
            target.push(k)
            count = countRecord[k]
        }else if( countRecord[k] == count ){
            target.push(k)
        }
    }
    let regex = new RegExp(`[${target.join('')}]`,'g')
    console.log(line.replace(regex,''))
})