题解 | #奇偶统计#
奇偶统计
https://www.nowcoder.com/practice/04de8eb0ecab426fa6be3ae99af17210
#include <stdio.h>
int main() {
long long cin, count, i;
long long a;
cin = 0, count = 0;
scanf("%lld", &a);
for (i = 1; i <= a; i++) {
if (i % 2 == 1)
count++;
else
cin++;
}
printf("%lld %lld", count, cin);
}
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