DDPM公式草稿2

q(xt1xt)=q(xt,xt1)q(xt)=q(xtxt1)q(xt1)q(xt)xt=αtxt1+1αtztN(αtxt1,(1αt)I)xt=αtx0+1αtztN(αtx0,1αtI)q(xtxt1)N(αtxt1,(1αt)I)q(xt)N(αtx0,1αtI)q(xt1)N(αt1x0,1αt1I)N(μ,σ)12πσexp((xμ)22σ2)q(xtxt1)q(xt1)q(xt)exp{12((xtαtxt1)21αt+(xt1αt1x0)21αt1(xtαtx0)21αt)}exp{12((αtβt+11αt1)xt122(αtxtβt+αt1x01αt1)xt1+C)}exp{12(Axt12+Bxt1+C)}exp{12(A(xt1+B2A)2+C)}q(x_{t-1}|x_t)=\frac{q(x_t,x_{t-1})}{q(x_t)}=\frac{q(x_t|x_{t-1})q(x_{t-1})}{q(x_t)} \\ \\ \begin{aligned} \because x_t&=\sqrt{\alpha_t}x_{t-1}+\sqrt{1-\alpha_t}z_t \sim N(\sqrt{\alpha_tx_{t-1}},(1-\alpha_t)I ) \\ x_t&=\sqrt{\overline{\alpha_t}}x_{0}+\sqrt{1-\overline{\alpha_t}}z_t \sim N(\sqrt{\overline{\alpha_t}}x_{0},\sqrt{1-\overline{\alpha_t}}I)\\ \quad \\ \therefore \quad& q(x_t|x_{t-1})\sim N(\sqrt{\alpha_tx_{t-1}},(1-\alpha_t)I )\\ \quad& q(x_t)\sim N(\sqrt{\overline{\alpha_t}}x_{0},\sqrt{1-\overline{\alpha_t}}I)\\ \quad& q(x_{t-1})\sim N(\sqrt{\overline{\alpha_{t-1}}}x_{0},\sqrt{1-\overline{\alpha_{t-1}}}I)\\ \quad \\ \because \quad & N(\mu,\sigma)\propto \frac{1}{\sqrt{2\pi}\sigma} exp(-\frac{(x-\mu)^2}{2\sigma^2}) \\ \therefore \quad& \frac{q(x_t|x_{t-1})q(x_{t-1})}{q(x_t)} \propto exp\lbrace -\frac{1}{2} (\frac{(x_t-\sqrt{\alpha_t}x_{t-1})^2}{1-\alpha_t} + \frac{(x_{t-1}-\sqrt{\overline{\alpha_{t-1}}}x_{0})^2}{1-\overline{\alpha_{t-1}}} - \frac{(x_t-\sqrt{\overline{\alpha_{t}}}x_{0})^2}{1-\overline{\alpha_{t}}})\rbrace \\ &\quad \quad \quad \quad \quad \quad \quad \quad \propto exp\lbrace -\frac{1}{2} ( (\frac{\alpha_t}{\beta_t}+\frac{1}{1-\overline{\alpha_{t-1}}})x_{t-1}^{2} - 2(\frac{\sqrt{\alpha_t}x_t}{\beta_t}+\frac{\sqrt{\overline{\alpha_{t-1}}}x_0}{1-\overline{\alpha_{t-1}}})x_{t-1}+\overline{C} ) \rbrace \\ &\quad \quad \quad \quad \quad \quad \quad \quad \propto exp \lbrace -\frac{1}{2}(Ax_{t-1}^{2}+Bx_{t-1}+C) \rbrace\\ &\quad \quad \quad \quad \quad \quad \quad \quad \propto exp \lbrace -\frac{1}{2}(A(x_{t-1}+\frac{B}{2A})^2+C) \rbrace \end{aligned} \\
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不愿透露姓名的神秘牛友
08-20 19:41
那一天的Java_J...:简历完全流水账,学生思维很严重,还有很大的优化空间,可以多看看牛客的简历。
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