题解 | #从单向链表中删除指定值的节点#
从单向链表中删除指定值的节点
https://www.nowcoder.com/practice/f96cd47e812842269058d483a11ced4f
a = list(map(int, input().split()))
b = []
b.append(a[1])
c = a[0]
for i in range(c-1):
e = b.index(a[2:][2*i+1])+1
b.insert(e,a[2:][2*i])
for i in range(b.count(a[-1])):
b.remove(a[-1])
print(' '.join(list(map(str, b))))
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