题解 | #从单向链表中删除指定值的节点#
从单向链表中删除指定值的节点
https://www.nowcoder.com/practice/f96cd47e812842269058d483a11ced4f
while 1:
try:
raw = [int(s) for s in input().split()]
num, head, dd = raw[0], raw[1], raw[-1]
one = list()
for i in range(2, len(raw) - 2, 2):
one.append((raw[i + 1], raw[i]))
linkList = [head]
for o in one:
index = linkList.index(o[0])
linkList.insert(index + 1, o[1])
linkList.remove(dd)
print(' '.join([str(i) for i in linkList]))
except:
break
