题解 | #简单密码#暴力解法

简单密码

https://www.nowcoder.com/practice/7960b5038a2142a18e27e4c733855dac

#include<iostream>
#include<string>
using namespace std;

int passcodeChange(string str) {
    string strnew;
    for (int i = 0; i < str.size(); i++) {
        if (str[i] >= 'a' && str[i] <= 'z') {
            switch (str[i]) {
                case 'a':
                case 'b':
                case 'c':
                    strnew.push_back('2');
                    break;
                case 'd':
                case 'e':
                case 'f':
                    strnew.push_back('3');
                    break;
                case 'g':
                case 'h':
                case 'i':
                    strnew.push_back('4');
                    break;
                case 'j':
                case 'k':
                case 'l':
                    strnew.push_back('5');
                    break;
                case 'm':
                case 'n':
                case 'o':
                    strnew.push_back('6');
                    break;
                case 'p':
                case 'q':
                case 'r':
                case 's':
                    strnew.push_back('7');
                    break;
                case 't':
                case 'u':
                case 'v':
                    strnew.push_back('8');
                    break;
                case 'w':
                case 'x':
                case 'y':
                case 'z':
                    strnew.push_back('9');
                    break;
                default:
                    break;
            }
        } else if (str[i] >= 'A' && str[i] <= 'Z') {
            if (str[i] == 'Z') {
                strnew.push_back('a');
            } else {
                strnew.push_back(str[i] + 'a' - 'A' + 1);
            }
        } else {
            strnew.push_back(str[i]);
        }
    }
    cout << strnew << endl;
    return 0;
}

int main() {
    string str;
    while (cin >> str) {
        passcodeChange(str);
    }
    return 0;
}

#华为笔试#
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