题解 | #姓名与学号#
姓名与学号
http://www.nowcoder.com/practice/ab68195587de46c59e2d327a4942d345
my_dict_1 = {'name': 'Niuniu','Student ID': 1}
my_dict_2 = {'name': 'Niumei','Student ID': 2}
my_dict_3 = {'name': 'Niu Ke Le','Student ID': 3}
dict_list = []
dict_list.append(my_dict_1)
dict_list.append(my_dict_2)
dict_list.append(my_dict_3)
'''
dict_list:
[{'name': 'Niuniu', 'Student ID': 1},
{'name': 'Niumei', 'Student ID': 2},
{'name': 'Niu Ke Le', 'Student ID': 3}]
其中：
dict_list[0]={'name': 'Niuniu', 'Student ID': 1}
dict_list[0]['name']=Niuniu
dict_list[0]['Student ID']=1
'''
for i in dict_list:
print(f"{i['name']}'s student id is {i['Student ID']}.")
my_dict_2 = {'name': 'Niumei','Student ID': 2}
my_dict_3 = {'name': 'Niu Ke Le','Student ID': 3}
dict_list = []
dict_list.append(my_dict_1)
dict_list.append(my_dict_2)
dict_list.append(my_dict_3)
'''
dict_list:
[{'name': 'Niuniu', 'Student ID': 1},
{'name': 'Niumei', 'Student ID': 2},
{'name': 'Niu Ke Le', 'Student ID': 3}]
其中：
dict_list[0]={'name': 'Niuniu', 'Student ID': 1}
dict_list[0]['name']=Niuniu
dict_list[0]['Student ID']=1
'''
for i in dict_list:
print(f"{i['name']}'s student id is {i['Student ID']}.")
