题解 | #把字符串转换成整数(atoi)#
https://www.nowcoder.com/practice/d11471c3bf2d40f38b66bb12785df47f
依次遍历 s 的每个字符,根据要求求解,当首字母是 "+-" 时,影响数字符号,其他情况判断字符是否为 "0-9",然后将数字拼接起来,最终判断结果是否超过范围
class Solution: def StrToInt(self , s: str) -> int: # write code here res = 0 flag = True for i, c in enumerate(s.strip()): if i == 0: if c == "-": flag = False elif c == "+": continue elif "0" <= c <= "9": res = res * 10 + int(c) else: break else: if "0" <= c <= "9": res = res * 10 + int(c) else: break if not flag: res = -res if res < - 2 ** 31: res = - 2 ** 31 elif res > 2 ** 31 - 1: res = 2 ** 31 - 1 return res
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