美团8.22笔试(5题) 投票
补个第五题AC的 python 版本，A 、B哪个队伍人少，就优先把能量高的人安排进去
x, y = [int(_) for _ in sys.stdin.readline().strip().split()]
power = [int(_) for _ in sys.stdin.readline().strip().split()]
power = sorted([ (e,i) for i, e in enumerate(power)], key = lambda x: [-x[0], x[1]])
if x == y:
print("A" * x + "B" * y)
else:
res = []
if x > y:
res = list("B" * (x + y))
for e, i in power[y:]:
res[i] = "A"
else:
res = list("A" * (x + y))
for e, i in power[x:]:
res[i] = "B"
print("".join(res)) 
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