题解 | #查找两个字符串a,b中的最长公共子串#,全靠硬编码实现
查找两个字符串a,b中的最长公共子串
http://www.nowcoder.com/practice/181a1a71c7574266ad07f9739f791506
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;
import java.util.Set;
// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
// 注意 hasNext 和 hasNextLine 的区别
while (in.hasNext()) { // 注意 while 处理多个 case
String str1 = in.next();
String str2 = in.next();
char[] chars1 = str1.toCharArray();
char[] chars2 = str2.toCharArray();
int length1 = chars1.length;
int length2 = chars2.length;
String str = "";
// 确保拿最小的字符串去对比
if (length1 <= length2){
str = getStr(chars1, chars2);
}else {
str = getStr(chars2, chars1);
}
System.out.println(str);
}
}
public static String getStr(char[] chars1,char[] chars2){
HashMap<Integer, Integer> map = new HashMap<>();
for (int i = 0; i < chars1.length; i++) {
char c1 = chars1[i];
for (int j = 0; j < chars2.length; j++) {
char c2 = chars2[j];
if (c2 == c1 ){
int count = 1;
// 如果两个字符串有一个后面没有元素则不进入循环
for (int k = i + 1,z = j + 1; k < chars1.length && z < chars2.length; k++,z++) {
if (chars1[k] == chars2[z]){
count++;
continue;
}
break;
}
Integer integer = map.get(i);
// 如果有更长的字串,使用长的那个
if (integer != null ){
int max = Math.max(integer, count);
map.put(i,max);
continue;
}
map.put(i,count);
}
}
}
Set<Map.Entry<Integer, Integer>> entries = map.entrySet();
int maxValue = 0;
int index = 0;
for (Map.Entry<Integer, Integer> entry : entries) {
Integer value = entry.getValue();
int max = Math.max(maxValue, value);
if (max != maxValue){
maxValue = max;
index = entry.getKey();
}
}
String s = new String(chars1);
return s.substring(index,index + maxValue);
}
}