题解 | #质数因子#
单词倒排
http://www.nowcoder.com/practice/81544a4989df4109b33c2d65037c5836
思路很简单:
1. 将字符串用特殊字符的正则劈成字符串数组 [^A-Za-z]+
2. 然后将字符串数中间加空格组倒序输出
import java.util.*;
public class Main{public static void main(String[] args){
Scanner sc=new Scanner(System.in);
while(sc.hasNextLine()){
String str=sc.nextLine();
String[] lts=str.split("[^A-Za-z]+");
for(int i=lts.length-1;i>=0;i--){
System.out.print(lts[i]+" ");
}
}
}
}