题解 | #数组元素反转#

#include using namespace std;

int main() {

int arr[6] = { 0 };//定义6个数的数组，初始化为0

int len = sizeof(arr) / sizeof(int);

for (int i = 0; i < len; i++) {
    cin >> arr[i];//从键盘获取6个整数
}

cout << "[";
for (int i = 0; i < len; i++) {
    if (i == len - 1) {
        cout << arr[i] << "]" << endl;
        break;
    }
    cout << arr[i] << ", ";
}

// write your code here......
//首尾分别交换位置，直到数组中间
int temp;
for(int i =0,j=len-1; i <= j; i++,j--)
{
        temp = arr[i];
        arr[i] = arr[j];
        arr[j] = temp;
}

cout << "[";
for (int i = 0; i < len; i++) {
    if (i == len - 1) {
        cout << arr[i] << "]" << endl;
        break;
    }
    cout << arr[i] << ", ";
}

return 0;

}