题解 | #连续子数组的最大和(二)#
连续子数组的最大和(二)
http://www.nowcoder.com/practice/11662ff51a714bbd8de809a89c481e21
#coding:utf-8
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param array int整型一维数组
# @return int整型一维数组
#
class Solution:
def FindGreatestSumOfSubArray(self , array ):
# write code here
retSum = array[0]
pre = cur = array[0]
left = right = 0
resl = resr = 0
for idx, item in enumerate(array):
if idx == 0:
continue
right += 1
cur = max(pre+item, item)
# print("cur:%d, left:%d, right:%d" %(cur, left, right))
if pre + item < item:
left = right
# print(left)
if (cur > retSum) or (cur == retSum and (right-left+1) > (resr-resl+1)):
resl = left
resr = right
retSum = cur
pre = cur
return array[resl:resr+1]
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param array int整型一维数组
# @return int整型一维数组
#
class Solution:
def FindGreatestSumOfSubArray(self , array ):
# write code here
retSum = array[0]
pre = cur = array[0]
left = right = 0
resl = resr = 0
for idx, item in enumerate(array):
if idx == 0:
continue
right += 1
cur = max(pre+item, item)
# print("cur:%d, left:%d, right:%d" %(cur, left, right))
if pre + item < item:
left = right
# print(left)
if (cur > retSum) or (cur == retSum and (right-left+1) > (resr-resl+1)):
resl = left
resr = right
retSum = cur
pre = cur
return array[resl:resr+1]

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