题解 | #自守数#
自守数
http://www.nowcoder.com/practice/88ddd31618f04514ae3a689e83f3ab8e
while True: try: n = int(input()) if n<1 or n>10000: break count = 0 for i in range(0,n+1): # 获得平方数的字符串 pf = str(i*i) # 获得i的长度 len_i = len(str(i)) # 获得平方的长度 len_pf = len(pf) if str(i) in pf[(len_pf-len_i)::1]: count +=1 print(count)
except:
break