题解 | #牛牛的字符矩形#

int main(){ char ch; //打印的符号 int num = 5; //对角线数目 int i,j1,j2; //j为行数 scanf("%c",&ch);

//upper打印上半角
for( i=0; i< (num-1)/2; i++){
    j2 = i*2+1;      //符号数
    j1 = (num-j2)/2; //空格数
    while( j1-->0 ) 
        printf(" ");
    while( j2-->0 )
        printf("%c",ch);
    printf("\n");
}

//middle打印中间行
j2 = num;
while( j2-->0 )
    printf("%c",ch);
printf("\n");

//lower下半角
for( i= (num-1)/2+1; i< num; i++ ){
    j1 = i-(num-1)/2; //空格数
    j2 = num-j1*2;    //符号数
    while( j1-->0 ) 
        printf(" ");
    while( j2-->0 )
        printf("%c",ch);
    printf("\n");
}

//end
return 0;

}