题解 | #N阶楼梯上楼问题#
N阶楼梯上楼问题
http://www.nowcoder.com/practice/c978e3375b404d598f1808e4f89ac551
#include<iostream>
using namespace std;
int main(){//相当于用递推法求斐波那契数列
int n;
int counter[91];
counter[0] = 0;
counter[1] = 1;
counter[2] = 2;
for(int i=3;i<=90;i++){
counter[i] = counter[i-1]+counter[i-2];
}
while(cin>>n){
cout<<counter[n]<<endl;
}
return 0;
}
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