题解 | #井字棋#
井字棋
http://www.nowcoder.com/practice/0375c1d206ef48a3894f72aa07b2fdde
#include <stdio.h>
void CSH(char qipan[3][3]) //接收棋盘
{
for(int i = 0;i<3;++i)
for(int j = 0;j<3;++j)
scanf("%c ",&qipan[i][j]);
}
char Winer(char qipan[3][3]) //判断棋盘获胜者
{
for(int i = 0;i<3;++i)
{
if(qipan[0][i]==qipan[1][i]&& qipan[1][i]==qipan[2][i] &&qipan[1][i]!='O') //行相同
return qipan[0][i];
if(qipan[i][0]==qipan[i][1]&& qipan[i][1]==qipan[i][2] &&qipan[i][1]!='O') //列相同
return qipan[i][0];
}
if(qipan[0][0]==qipan[1][1] && qipan[1][1]==qipan[2][2] && qipan[1][1]!='O') //对角线相同
return qipan[1][1];
if(qipan[0][2]==qipan[1][1] && qipan[1][1]==qipan[2][0] && qipan[1][1]!='O')
return qipan[1][1];
return 'O'; //都不相同
}
int main()
{
char qipan[3][3]={0};
CSH(qipan);
char x = Winer(qipan); //接收
if(x == 'K') printf("KiKi wins!\n");
else if(x == 'B') printf("BoBo wins!\n");
else printf("No winner!\n");
return 0;
}
