题解 | #奇偶统计#
奇偶统计
http://www.nowcoder.com/practice/04de8eb0ecab426fa6be3ae99af17210
#include <stdio.h>
int main(void)
{
int n = 0;
scanf("%d", &n);
if (0 == n % 2) {
printf("%d %d", n / 2, n / 2);
}
else {
printf("%d %d", n / 2 + 1, n / 2);
}
return 0;
}
