题解 | #二叉树的镜像#
二叉树的镜像
http://www.nowcoder.com/practice/a9d0ecbacef9410ca97463e4a5c83be7
头节点放入队列中, 当队列不为空的时候一致进行处理
弹出的节点,先将其左右子树进行交换, 再将变换后的左,右节点一次放入队列
package com.yzcOfffer.JZ27;
import java.util.LinkedList;
import java.util.Queue;
/**
* @author YZC
* @date 2021/12/6 17:15
*/
class TreeNode {
int val = 0;
TreeNode left = null;
TreeNode right = null;
@Override
public String toString() {
return "TreeNode{" +
"val=" + val +
", left=" + left +
", right=" + right +
'}';
}
public TreeNode(int val) {
this.val = val;
}
}
public class Solution {
public static void main(String[] args) {
TreeNode node1 = new TreeNode(8);
TreeNode node2 = new TreeNode(6);
TreeNode node3 = new TreeNode(10);
TreeNode node4 = new TreeNode(5);
TreeNode node5 = new TreeNode(7);
TreeNode node6 = new TreeNode(9);
TreeNode node7 = new TreeNode(11);
node1.left = node2;
node1.right = node3;
node2.left = node4;
node2.right= node5;
node3.right = node7;
node3.left = node6;
System.out.println(Mirror(node1));
}
public static TreeNode Mirror(TreeNode root) {
if (root == null) {
return null;
}
Queue<TreeNode> queue = new LinkedList<>();
//头节点加入队列
queue.add(root);
while (!queue.isEmpty()) {
TreeNode node = queue.poll();
//交换node节点的两个子节点
TreeNode left = node.left;
node.left = node.right;
node.right = left;
//如果当前节点的左子树不为空,就把左子树节点加入到队列中
if (node.left != null) {
queue.add(node.left);
}
//如果当前节点的右子树不为空,就把右子树
//节点加入到队列中
if (node.right != null) {
queue.add(node.right);
}
}
return root;
}
}
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