题解 | #字符串合并处理# python进制转换
字符串合并处理
http://www.nowcoder.com/practice/d3d8e23870584782b3dd48f26cb39c8f
while True:
try:
A, B =input().split()
except:
break
else:
in_str = list(A+B)
in_str[0::2] = sorted(in_str[0::2])
in_str[1::2] = sorted(in_str[1::2])
list_transform = in_str
for i in range(len(list_transform)):
ascii = ord(list_transform[i])
# 用ascii判断是否0-9 a-f
if ascii in range(48,58) or ascii in range(65,71) or ascii in range(97,103):
# zill为了对付0-9的二进制反转后为自身，如1-> 0001 -> 1 (1000)
sub_list = str(bin(int(list_transform[i], 16)))[2:].zfill(4)
sub_list = list(sub_list)
sub_list.reverse()
bin_ele = ''.join(sub_list)
char_ele = str(hex(int(bin_ele, 2))[2:]).upper()
list_transform[i] = char_ele
list_transform = ''.join(list_transform)
print(list_transform)
