题解 | #输出单向链表中倒数第k个结点#
输出单向链表中倒数第k个结点
http://www.nowcoder.com/practice/54404a78aec1435a81150f15f899417d
while True:
try:
count = int(input())
input_str = input().strip().split(" ")
k = int(input())
if k == 0:
print(0)
continue
print(input_str[-k])
except EOFError:
break
用了数组还快点。。。
