题解 | #删除字符串中出现次数最少的字符#
删除字符串中出现次数最少的字符
http://www.nowcoder.com/practice/05182d328eb848dda7fdd5e029a56da9
#一开始以为要分三种情况，即abb,aabbddd,ddddd,后来发现不用,都用最后那几行统一处理即可
while True:
try:
s=input()
ss=set(s)
adict={}
snew=''
for i in ss:
adict[i]=s.count(i)
alist=sorted(adict.items(),key=lambda stu:stu[1])
# print(alist)
# if alist[0][1]<alist[1][1]:
# print(s.replace(alist[0][0],''))
# elif alist[0]==alist[-1]:
# print()
# else :
subs = ''
for item in alist:
if item[1]==alist[0][1]:
subs+=item[0]
for i in subs:
s=s.replace(i,'')
print(s)
except:
break
