题解 | #跳台阶#
跳台阶
http://www.nowcoder.com/practice/8c82a5b80378478f9484d87d1c5f12a4
# -*- coding:utf-8 -*- class Solution: def jumpFloor(self, number): # write code here if number<=2: return number F_pre = 1 F_cur = 2 cnt = 2 while cnt<number: F = F_cur + F_pre cnt = cnt + 1 F_pre = F_cur F_cur = F return F