题解 | #跳台阶#
跳台阶
http://www.nowcoder.com/practice/8c82a5b80378478f9484d87d1c5f12a4
# -*- coding:utf-8 -*-
class Solution:
def jumpFloor(self, number):
# write code here
if number<=2: return number
F_pre = 1
F_cur = 2
cnt = 2
while cnt<number:
F = F_cur + F_pre
cnt = cnt + 1
F_pre = F_cur
F_cur = F
return F 
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