题解 | #KiKi设计类继承#
KiKi设计类继承
http://www.nowcoder.com/practice/699ba050e2704591ae3e62401a856b0e
#include<stdio.h>
int main()
{
int n, i, j;
scanf("%d", &n);
int a[n];
for(i = 0; i < n; i++){
scanf("%d", &a[i]);
}
for(i = 0; i < n - 1; i++){
for(j = i+1; j < n; j++){
if(a[i] == a[j]){
a[j] = 0;
}
}
}
for(i = 0; i < n; i++){
if(a[i] != 0){
printf("%d ", a[i]);
}
}
return 0;
} 
