题解 | #KiKi说祝福语#
简单计算器
http://www.nowcoder.com/practice/b8f770674ba7468bb0a0efcc2aa3a239
#include<stdio.h>
int main()
{
double n1,n2;
char c;
while(~scanf("%lf",&n1)){
c = getchar();
scanf("%lf",&n2);
if(c=='+'){
printf("%.4lf%c%.4lf=%.4lf\n",n1,c,n2,n1+n2);
}
else if(c=='-'){
printf("%.4lf%c%.4lf=%.4lf\n",n1,c,n2,n1-n2);
}
else if(c=='*'){
printf("%.4lf%c%.4lf=%.4lf\n",n1,c,n2,n1*n2);
}
else if(c=='/'){
if(n2==0.0){
printf("Wrong!Division by zero!\n");
}
else
printf("%.4lf%c%.4lf=%.4lf\n",n1,c,n2,n1/n2);
}
else{
printf("Invalid operation!\n");
}
}
return 0;
}
