序列的美观度
序列的美观度
https://ac.nowcoder.com/acm/contest/9983/I
思路
- 如果是连续相同的序列一定需要保留
如果是不连续则记录下来,后面遇到有相同的就删掉其他那些
代码
// Problem: 序列的美观度 // Contest: NowCoder // URL: https://ac.nowcoder.com/acm/contest/9983/I // Memory Limit: 524288 MB // Time Limit: 4000 ms // Powered by CP Editor (https://github.com/cpeditor/cpeditor) #include <bits/stdc++.h> using namespace std; #define pb push_back #define mp(aa,bb) make_pair(aa,bb) #define _for(i,b) for(int i=(0);i<(b);i++) #define rep(i,a,b) for(int i=(a);i<=(b);i++) #define per(i,b,a) for(int i=(b);i>=(a);i--) #define mst(abc,bca) memset(abc,bca,sizeof abc) #define X first #define Y second #define lowbit(a) (a&(-a)) #define debug(a) cout<<#a<<":"<<a<<"\n" typedef long long ll; typedef pair<int,int> pii; typedef unsigned long long ull; typedef long double ld; const int N=1000010; const int INF=0x3f3f3f3f; const int mod=1e9+7; const double eps=1e-6; const double PI=acos(-1.0); int a[N],ans; set<int> s; void solve(){ int n;cin>>n; rep(i,1,n) cin>>a[i]; rep(i,1,n){ if(s.find(a[i])==s.end()) s.insert(a[i]); else { ans++; if(s.size()>1) { s.clear(); s.insert(a[i]); } } } cout<<ans<<"\n"; } int main(){ ios::sync_with_stdio(0);cin.tie(0); // int t;cin>>t;while(t--) solve(); return 0; }