(数学) 输出第n个丑数

function GetUglyNumber_Solution(index)
{
    // write code here
    if(index==0) return 0
    let ugly = [1]
    let two = 0, three = 0, five =0
    for(let i=1;i<index;i++){
        ugly[i]= Math.min(2*ugly[two],3*ugly[three],5*ugly[five])
        if(ugly[i] == 2*ugly[two]) two++
        if(ugly[i] == 3*ugly[three]) three++
        if(ugly[i] == 5*ugly[five]) five++
    }
    return ugly[index-1]
}