两次递归
树的子结构
http://www.nowcoder.com/questionTerminal/6e196c44c7004d15b1610b9afca8bd88
class Solution:
def HasSubtree(self, s, t):
def sametree(p,q):
if p is None and q is None:
return True
elif p is not None and q is not None and p.val==q.val:
return sametree(p.left,q.left) and sametree(p.right,q.right)
elif p is not None and q is None:
return True
else:
return False
def subtree(s,t):
if s is None or t is None:return False
if sametree(s,t):
return True
return subtree(s.left,t) or subtree(s.right,t)
return subtree(s,t)两次递归
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