题解 | #字符串反转#
扑克牌大小
http://www.nowcoder.com/practice/d290db02bacc4c40965ac31d16b1c3eb
#include <string.h> #include #include #include using namespace std; int main() { string a; while(cin>>a) { int n = a.length(); for(int i=n-1;i>=0;i--) { cout << a[i]; }
}
return(0);
}