这个思路太妙了,应该是本题的正解了,但是应该s1,s2都有一个emp_no = 10001的约束 select sum(s2.salary - s1.salary) from salaries s1 inner join salaries s2 on s1.emp_no = 10001 and s2.emp_no = 10001 and s1.to_date = s2.from_date;
3

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