题解 | 牛牛的矩阵相加
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
第一次：
list = [
[ 1,2,3],
[4,5,6],
[7,8,9]
]
n = int(input())
list_1= []
for i in list:
list_2 = []
for j in i:
list_2.append(j*n)
list_1.append(list_2)
print(list_1)
matrix = [[1, 2, 3], [4, 5, 6], [7, 8, 9]] n = int(input()) # 一行搞定：遍历每一行 row，再遍历行里的每个元素 x result = [[x * n for x in row] for row in matrix] print(result)
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