题解 | 时间转换

#include <stdio.h>

int main() {
   int sec = 0;
   scanf("%d",&sec);
   int hour = 0;
   int minute = 0;
   int secs = 0;
   if(sec>3600)
   {
    hour = sec / 3600;
    minute = (sec-(hour*3600)) / 60;
    secs = sec - (hour*3600)-(minute*60);
    
   }
   else {
    hour = sec /3600;
    minute = sec / 60;
    secs = sec - minute*60;
   }
   printf("%d %d %d",hour,minute,secs);
    return 0;
}

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