题解 | 岛屿数量
岛屿数量
https://www.nowcoder.com/practice/5225a111760b46c2be897d97b4d8561f
#include <iostream>
#include <vector>
using namespace std;
const int N = 110;
char g[N][N];
bool st[N][N];
int dx[8] = {0,0,-1,-1,-1,1,1,1};
int dy[8] = {1,-1,0,-1,1,-1,0,1};
int n,m;
void dfs(int x,int y){
st[x][y] = true;
for(int i = 0;i < 8;i++){
int nx = x + dx[i];
int ny = y + dy[i];
if(nx >= 1 && nx <= n && ny >= 1 && ny <= m && !st[nx][ny] && g[nx][ny] == 'W'){
st[nx][ny] = true;
dfs(nx,ny);
}
}
}
int main() {
cin>>n>>m;
vector<pair<int,int>> key;
for(int i = 1;i <= n;i++){
for(int j = 1;j <= m;j++){
cin>>g[i][j];
if(g[i][j] == 'W'){
key.push_back({i,j});
}
}
}
int cnt = 0;
for(const auto& t : key){
if(!st[t.first][t.second]){
cnt++;
dfs(t.first,t.second);
}
}
cout<<cnt;
}
// 64 位输出请用 printf("%lld")

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