题解 | 奇偶统计
奇偶统计
https://www.nowcoder.com/practice/04de8eb0ecab426fa6be3ae99af17210
#include <iostream>
using namespace std;
int main() {
int n, sum1 = 0, sum2 = 0;
cin >> n;
for(int i = 1; i <= n; i ++){
if(i % 2 == 1) sum1 ++;
else sum2 ++;
}
cout << sum1 <<" "<< sum2;
return 0;
}
文远知行公司福利 588人发布